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Bertrand paradox (probability)

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190:. This issue can be avoided by "regularizing" the problem so as to exclude diameters, without affecting the resulting probabilities. But as presented above, in method 1, each chord can be chosen in exactly one way, regardless of whether or not it is a diameter; in method 2, each diameter can be chosen in two ways, whereas each other chord can be chosen in only one way; and in method 3, each choice of midpoint corresponds to a single chord, except the center of the circle, which is the midpoint of all the diameters. 305:
the chords on that smaller circle needs to be the same as the restricted distribution of chords on the larger circle (again using extension/restriction of the generating straws). Thus, if the smaller circle is moved around within the larger circle, the restricted distribution should not change. It can be seen very easily that there would be a change for method 3: the chord distribution on the small red circle looks qualitatively different from the distribution on the large circle:
352:"Method 2" is the only solution that fulfills the transformation invariants that are present in certain physical systems—such as in statistical mechanics and gas physics—in the specific case of Jaynes's proposed experiment of throwing straws from a distance onto a small circle. Nevertheless, one can design other practical experiments that give answers according to the other methods. For example, in order to arrive at the solution of "method 1", the 309: 225: 215: 205: 257: 247: 237: 143: 107: 79: 343:
Likewise, "method 1" is the unique invariant distribution for a scenario where a spinner is used to select one endpoint of the chord, and then used again to select the orientation of the chord. Here the invariance in question consists of rotational invariance for each of the two spins. It is also the
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To illustrate: assume that chords are laid at random onto a circle with a diameter of 2, say by throwing straws onto it from far away and converting them to chords by extension/restriction. Now another circle with a smaller diameter (e.g., 1.1) is laid into the larger circle. Then the distribution of
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The "random endpoints" method: Choose two random points on the circumference of the circle and draw the chord joining them. To calculate the probability in question imagine the triangle rotated so its vertex coincides with one of the chord endpoints. Observe that if the other chord endpoint lies on
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proposed a solution to Bertrand's paradox based on the principle of "maximum ignorance"—that we should not use any information that is not given in the statement of the problem. Jaynes pointed out that Bertrand's problem does not specify the position or size of the circle and argued that therefore
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to the radius. The chord is longer than a side of the triangle if the chosen point is nearer the center of the circle than the point where the side of the triangle intersects the radius. The side of the triangle bisects the radius, therefore the probability a random chord is longer than a side of
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method, one can affix a spinner to the center of the circle, and let the results of two independent spins mark the endpoints of the chord. In order to arrive at the solution of "method 3", one could cover the circle with molasses and mark the first point that a fly lands on as the midpoint of the
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In a 2015 article, Alon Drory argued that Jaynes' principle can also yield Bertrand's other two solutions. Drory argues that the mathematical implementation of the above invariance properties is not unique, but depends on the underlying procedure of random selection that one uses (as mentioned
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the arc between the endpoints of the triangle side opposite the first point, the chord is longer than a side of the triangle. The length of the arc is one third of the circumference of the circle, therefore the probability that a random chord is longer than a side of the inscribed triangle is
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However, Jaynes did not just use invariances to accept or reject given methods: this would leave the possibility that there is another not yet described method that would meet his common-sense criteria. Jaynes used the integral equations describing the invariances to directly determine the
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The problem's classical solution (presented, for example, in Bertrand's own work) depends on the method by which a chord is chosen "at random". The argument is that if the method of random selection is specified, the problem will have a well-defined solution (determined by the principle of
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above, Jaynes used a straw-throwing method to choose random chords). He shows that each of Bertrand's three solutions can be derived using rotational, scaling, and translational invariance, concluding that Jaynes' principle is just as subject to interpretation as the
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The "random midpoint" method: Choose a point anywhere within the circle and construct a chord with the chosen point as its midpoint. The chord is longer than a side of the inscribed triangle if the chosen point falls within a concentric circle of radius
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indifference). The three solutions presented by Bertrand correspond to different selection methods, and in the absence of further information there is no reason to prefer one over another; accordingly, the problem as stated has no unique solution.
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unique scale and rotation invariant distribution for a scenario where a rod is placed vertically over a point on the circle's circumference, and allowed to drop to the horizontal position (conditional on it landing partly inside the circle).
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For example, we may consider throwing a dart at the circle, and drawing the chord having the chosen point as its center. Then the unique distribution which is translation, rotation, and scale invariant is the one called "method 3" above.
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The same occurs for method 1, though it is harder to see in a graphical representation. Method 2 is the only one that is both scale invariant and translation invariant; method 3 is just scale invariant, method 1 is neither.
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the radius of the larger circle. The area of the smaller circle is one fourth the area of the larger circle, therefore the probability a random chord is longer than a side of the inscribed triangle is
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The "random radial point" method: Choose a radius of the circle, choose a point on the radius and construct the chord through this point and
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chord. Several observers have designed experiments in order to obtain the different solutions and verified the results empirically.
324:. In this problem, the integral equations indeed have a unique solution, and it is precisely what was called "method 2" above, the 39: 871: 548: 402: 73:
Bertrand gave three arguments (each using the principle of indifference), all apparently valid yet yielding different results:
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any definite and objective solution must be "indifferent" to size and position. In other words: the solution must be both
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of the circle is chosen at random. What is the probability that the chord is longer than a side of the triangle?
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may not produce definite, well-defined results for probabilities if it is applied uncritically when the
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to the radius. To calculate the probability in question imagine the triangle rotated so a side is
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Other selection methods have been found. In fact, there exists an infinite family of them.
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Drory, Alon (2015), "Failure and Uses of Jaynes' Principle of Transformation Groups",
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These three selection methods differ as to the weight they give to chords which are
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Random chords, selection method 1; red = longer than triangle side, blue = shorter
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The Bertrand paradox is generally presented as follows: Consider an equilateral
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The Second Scientific American Book of Mathematical Puzzles and Diversions
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Marinoff, L. (1994), "A resolution of Bertrand's paradox",
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midpoints/chords chosen at random using the above methods.
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Jaynes's solution using the "maximum ignorance" principle
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Midpoints of the chords chosen at random using method 3
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Midpoints of the chords chosen at random using method 2
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Midpoints of the chords chosen at random using method 1
395:"Bertrand's Paradox and the Principle of Indifference" 194:
Scatterplots showing simulated Bertrand distributions,
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(March 1984), "Bertrand's Paradox", 640: 777:British Journal for the Philosophy of Science 8: 770:Gyenis, Zalán; RĂ©dei, MiklĂłs (1 June 2015), 685:(443), The Mathematical Association: 15–19, 285:In his 1973 paper "The Well-Posed Problem", 19:For other paradoxes by Joseph Bertrand, see 57: 460: 440: 438: 436: 434: 432: 365: 46:(1889) as an example to show that the 58:Bertrand's formulation of the problem 7: 21:Bertrand's paradox (disambiguation) 14: 505:The American Mathematical Monthly 260:Chords chosen at random, method 3 250:Chords chosen at random, method 2 240:Chords chosen at random, method 1 146:Random chords, selection method 3 110:Random chords, selection method 2 64:triangle inscribed in a circle 1: 772:"Defusing Bertrand's Paradox" 867:Probability theory paradoxes 649:University of Chicago Press 888: 837:More on Bertrand's Paradox 122:the inscribed triangle is 42:introduced it in his work 18: 16:Probability theory paradox 479:10.1007/s10701-015-9876-7 334:principle of indifference 48:principle of indifference 678:The Mathematical Gazette 587:"The Well-Posed Problem" 322:probability distribution 32:classical interpretation 30:is a problem within the 746:Clark, Michael (2012), 377:Calcul des probabilitĂ©s 52:domain of possibilities 44:Calcul des probabilitĂ©s 872:Mathematical paradoxes 595:Foundations of Physics 448:Foundations of Physics 312: 261: 251: 241: 229: 219: 209: 147: 111: 83: 749:Paradoxes from A to Z 549:Philosophy of Science 499:Bower, O. K. (1934). 403:Philosophy of Science 311: 259: 249: 239: 227: 217: 207: 145: 109: 81: 813:"Bertrand's Problem" 393:Shackel, N. (2007), 348:Physical experiments 862:Eponymous paradoxes 790:10.1093/bjps/axt036 608:1973FoPh....3..477J 471:2015FoPh...45..439D 829:Bertrand's Paradox 810:Weisstein, Eric W. 725:American Scientist 616:10.1007/BF00709116 313: 272:Classical solution 262: 252: 242: 230: 220: 210: 148: 112: 84: 36:probability theory 763:978-0-415-53857-2 662:978-0-226-28253-4 266: 265: 879: 840: 832: 823: 822: 797: 796:on 5 August 2014 792:, archived from 766: 752:(3rd ed.), 734: 733: 716: 710: 709: 672: 666: 665: 646: 633: 627: 626: 591: 579: 573: 572: 543: 537: 536: 496: 490: 489: 464: 442: 427: 426: 399: 390: 384: 381:Gauthier-Villars 373:Bertrand, Joseph 370: 354:random endpoints 200: 199: 181: 179: 178: 175: 172: 165: 163: 162: 159: 156: 137: 135: 134: 131: 128: 101: 99: 98: 95: 92: 28:Bertrand paradox 887: 886: 882: 881: 880: 878: 877: 876: 852: 851: 834: 826: 808: 807: 804: 769: 764: 745: 742: 740:Further reading 737: 718: 717: 713: 691:10.2307/3615385 674: 673: 669: 663: 637:Gardner, Martin 635: 634: 630: 589: 581: 580: 576: 545: 544: 540: 517:10.2307/2300418 498: 497: 493: 444: 443: 430: 397: 392: 391: 387: 371: 367: 363: 350: 283: 274: 198: 195: 176: 173: 170: 169: 167: 160: 157: 154: 153: 151: 132: 129: 126: 125: 123: 96: 93: 90: 89: 87: 60: 40:Joseph Bertrand 24: 17: 12: 11: 5: 885: 883: 875: 874: 869: 864: 854: 853: 850: 849: 824: 803: 802:External links 800: 799: 798: 784:(2): 349–373, 767: 762: 741: 738: 736: 735: 711: 667: 661: 628: 602:(4): 477–493, 574: 562:10.1086/289777 538: 511:(8): 506–510. 491: 455:(4): 439–460, 428: 416:10.1086/519028 410:(2): 150–175, 385: 364: 362: 359: 349: 346: 282: 279: 273: 270: 264: 263: 253: 243: 232: 231: 221: 211: 192: 184: 183: 139: 103: 59: 56: 15: 13: 10: 9: 6: 4: 3: 2: 884: 873: 870: 868: 865: 863: 860: 859: 857: 848: 844: 839: 838: 831: 830: 825: 820: 819: 814: 811: 806: 805: 801: 795: 791: 787: 783: 779: 778: 773: 768: 765: 759: 755: 751: 750: 744: 743: 739: 731: 727: 726: 721: 715: 712: 708: 704: 700: 696: 692: 688: 684: 680: 679: 671: 668: 664: 658: 654: 650: 645: 644: 638: 632: 629: 625: 621: 617: 613: 609: 605: 601: 597: 596: 588: 584: 583:Jaynes, E. 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Suppose a 61: 43: 27: 25: 847:3Blue1Brown 843:Numberphile 651:, pp.  296:translation 856:Categories 462:1503.09072 818:MathWorld 754:Routledge 720:Kac, Mark 707:158690181 570:122224925 525:0002-9890 383:, p. 5-6. 375:(1889), " 299:invariant 188:diameters 639:(1987), 585:(1973), 556:: 1–24, 487:88515906 424:15760612 336:itself. 328:method. 699:3615385 653:223–226 624:2380040 604:Bibcode 533:2300418 467:Bibcode 180:⁠ 168:⁠ 164:⁠ 152:⁠ 136:⁠ 124:⁠ 100:⁠ 88:⁠ 845:& 760:  705:  697:  659:  622:  568:  531:  523:  485:  422:  703:S2CID 695:JSTOR 620:S2CID 590:(PDF) 566:S2CID 529:JSTOR 483:S2CID 457:arXiv 420:S2CID 398:(PDF) 361:Notes 292:scale 68:chord 833:and 758:ISBN 657:ISBN 521:ISSN 294:and 26:The 841:by 786:doi 687:doi 612:doi 558:doi 513:doi 475:doi 412:doi 379:", 34:of 858:: 815:. 782:66 780:, 774:, 756:, 730:72 728:, 701:, 693:, 683:68 681:, 655:, 647:, 618:, 610:, 598:, 592:, 564:, 554:61 552:, 527:. 519:. 509:41 507:. 503:. 481:, 473:, 465:, 453:45 451:, 431:^ 418:, 408:74 406:, 400:, 301:. 182:. 38:. 821:. 788:: 689:: 614:: 606:: 600:3 560:: 535:. 515:: 477:: 469:: 459:: 414:: 177:4 174:/ 171:1 161:2 158:/ 155:1 138:. 133:2 130:/ 127:1 102:. 97:3 94:/ 91:1 23:.

Index

Bertrand's paradox (disambiguation)
classical interpretation
probability theory
Joseph Bertrand
principle of indifference
domain of possibilities
triangle inscribed in a circle
chord


perpendicular
perpendicular

diameters






Edwin Jaynes
scale
translation
invariant

probability distribution
principle of indifference
Bertrand, Joseph
Calcul des probabilités
"Bertrand's Paradox and the Principle of Indifference"

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