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I can't find it again... It's based on starting from a known point (x, y) anywhere on the circle of radius R, and moving to another spot on the circle by adding a velocity vector V = ( y/R, -x/R). Actually, the velocity vector V's magnitude |V| can be any fractional component. It's a nifty way to
152:
The domain of g(t) are the permissible values for t. You know the domain of f(x), so you know the permissible values for the argument of the function f, and in this case the argument is -t + 5. So, what values can t be if -t + 5 ≥ -4? The range of g(t) are the possible values that the function can
827:
Through various quirks of scheduling, a bit of self-study, and odd luck I managed to complete a BS in
Geology and an MS in Environmental Policy without ever once taking a course in statistics, not even in high school. At this point in my life it is a source of inward embarrassment and occasionally a
574:
I don't mean literally write a Taylor series, I just mean it's the same idea. The Taylor series says f(x+h)=f(x)+hf'(x)+(h/2)f''(x)+... . The integral you showed is a first-order approximation, so try writing out a few of the second-order correction terms and seeing what they look like. The point
398:(x,y+Δy)Δx, which we say is NOT equal to zero. Thus, the we are allowing for the fact that y is different between the two paths but are ignoring the variation of x along each of the paths. In other words, we are saying that the variation of F
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professional impediment. As such, I'd like to fill this gap in my knowledge on my own time. I would be grateful if someone could point me towards a reputable online source for statistics instruction from basically scratch?
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but I'm not sure how to arrive at this answer. I don't even know where to begin! If anyone could help, I would greatly appreciate it. Could someone tell me what steps would be necessary to get to the answer? --
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Perhaps the confusion comes from the use of x and y in two separate equations. (This is perfectly valid, but it can been disorienting.) Let's restate the second half of the problem as:
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0 (the two top sides are parallel to the x-axis). So we start by looking at the work done in travelling through the paths parallel to the x-axis. This is equal to
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obtain. You know the range of the function f(x), which is the same as the range of f(-x + 5) so what values can -2f(-x + 5) + 1 obtain if f(-x + 5) < -1?
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The page you are currently viewing is an archive page. While you can leave answers for any questions shown below, please ask new questions on one of the
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Suppose we wanted to calculate the work done in going around a small rectange in the xy plane with dimensions Δx and Δy, with (Δx,Δy)--: -->
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is so small, its square is swamped out by the first-order term. Try writing it out that way and seeing what the limit looks like as
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A function f(x) has domain {x e R | x ≥ -4} and range {y e R | y < -1}. Determine the domain and range of this function:
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Hmm, I seem to be having trouble seeing how to write the integral as a Taylor series. Can you please show me? Thanks!
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as constant over the y interval is equivalent to ignoring the terms with Δy, which is bad because that's everything.
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Because Δx is said to be small, F_x is assumed to be roughly constant over the interval x to x+Δx. Thus, we get W=F
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Just to clarify, R is the radius of the circle plotted. Fex, a circle of radius R = 10 would go like this...
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as constant over the x interval is equivalent to ignoring the terms with Δx, which is good. But treating F
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Should the
Schlafli symbol {6/2} be interpreted as a polygon compound or as a doubly-wound triangle?
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807:. That Schlafli symbol tells you to take 6 evenly spaced vertices and connect every second one.
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I remember reading about this years ago in wikipedia and now the name of the method escapes me.
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Does anyone know the name for the method of generating a circular path using the two equations
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are there any free & meritorious statistics lessons/courses to be found online?
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Define the function g(t) = -2f(-t+5) + 1. What are the domain and range of g(t)?
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383:{\displaystyle \int _{x+\Delta x,y+\Delta y}^{x,y+\Delta y}\!F_{x}(x,y)\,dx.}
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681:= F(x+Δx,y) - F(x,y). The Taylor expansion of F(x+Δx,y) is F + ΔxF
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It's got to be something simple, but looking under the list of
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isn't significant in comparison to Δy. Why would this be true?
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For the second integral we get F(x,y+Δy) - F(x+Δx,y+Δy) = -ΔxF
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Welcome to the
Knowledge Mathematics Reference Desk Archives
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name of method for generating a circular path in x, y plane
674:{\displaystyle \int _{x,y}^{x+\Delta x,y}\!F_{x}(x,y)\,dx}
274:{\displaystyle \int _{x,y}^{x+\Delta x,y}\!F_{x}(x,y)\,dx}
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104:How to find the domain and range of this function?
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844:http://ocw.mit.edu/OcwWeb/Mathematics/index.htm
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117:domain {x e R | x ≤ 9}, range { y e R | y : -->
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689:/2! +..., so we get F(x+Δx,y) - F(x,y) = ΔxF
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463:{\displaystyle F_{xx}(\Delta x)^{2}}
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879:List_of_numerical_analysis_topics
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987:23:26, 21 February 2010 (UTC)
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532:{\displaystyle \Delta y}
509:{\displaystyle \Delta x}
486:{\displaystyle \Delta x}
18:Knowledge:Reference desk
111:y = -2f ( -x + 5 ) + 1
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555:—Preceding
394:(x,y)Δx - F
188:Integration
124:—Preceding
99:February 21
67:February 22
46:February 20
26:Mathematics
940:Thanks! --
723:(x,y) - F
715:(x,y) - F
50:<<
805:hexagram
697:/2! +...
557:unsigned
126:unsigned
56:February
24: |
22:Archives
20: |
809:Rckrone
803:It's a
763:Rckrone
579:small.
89:pages.
956:CORDIC
934:-1.09
162:domain
923:-0.1
895:Step
866:Hi!
742:+ ΔyF
734:+ ΔyF
693:+ ΔxF
685:+ ΔxF
158:range
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63:: -->
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