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Talk:Ultraproduct

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filter's dual ideal). (If the filter is cofinite (Fréchet), its dual is the set of finite sets of indices.) The agreement set of a negation is the complement of the agreement set of the original formula, and the negation in the constructed model has the opposite truth value of the formula in the source model. disjunctions, conjunctions, and implications are only slightly more complex. Henle and Keinberg show the proof for disjunctions and existential quantifications, and challenge the reader to complete the proof for the other cases.
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By making these functions of the positive integers, and thus a subset of the ultraproduct model with all the first-order properties of the reals, it should be much easier to introduce students already familiar with the infinitesimal approach to calculus to the wider implications of nonstandard analysis. More advanced model theory including ultrafilters and the Axiom of Choice can be introduced afterward.
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In science, it frequently takes powerful methods or tools to make important discoveries that lesser tools may confirm. I think my polynomial ratios are an example of more modest tools that merely confirm the discovery Robinson made with model theory and ultraproducts, the most powerful tools at his
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The polynomial ratio functions of real numbers serve as a formal model and justification of Leibnizian calculus even without the full transfer principle. (Why did no one between Weierstrass and Robinson point out this model, and show the formalists were too hasty in throwing out the infinitesimals?)
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You're correct that the property of being an integer is not first-order definable in the reals (with plus and times as the only nonlogical symbols). But I'm afraid the argument you give is not a correct way to prove that. Consider a similar case: Every real number is either negative or nonnegative,
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As one can see by some of my work on Knowledge this year, I have some ideas about hyperreal numbers and nonstandard analysis that are still unpublished, and therefore are not yet ready for entry in this encyclopedia. They need some kicking around in an open forum. Does anyone know an internet
655:. Is it negative, or nonnegative? The smart-ass in me wants to answer, "Yes!" The correct answer is that this sequence does indeed require an ultrafilter to decide. But this sequence would never appear in a suitably limited subset of the set of all sequences like my polynomial ratio sequences. 560:, ...) is clearly a nonstandard integer, and all integers are either odd or even but not both. Is this sequence odd or even? One ultrafilter that includes to odd terms, say the sequence is odd. Another filter, with the even terms, says the sequence is even. Conclusion: Parity of integers is 467:
Hopeless? The case for negation of a simpler formula is the easiest part of the entire proof: The agreement set of indices for which the negation holds is the complement of the agreement set of the original formula. Complements of filter members are nonmembers of the filter (and members of the
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subsets of the naturals. It's an ultrafilter on a different Boolean algebra; namely, all finite and cofinite subsets of the naturals. That choice does make the negation step trivial. The hard part now becomes proving that the set of all indices where the proposition holds, is actually an
434:, would also imply the truth of the theorem as applied to models using suitably limited subsets of the entire set of sequences. Yet, this section concludes that "the fact that U is an ultrafilter (and not just a filter) is used in the negation clause." What negation clause? 555:
Ultrafilters can define when higher order formulae hold, but may disagree with other ultrafilters. This shows that the formula cannot be rephrased in first order terms within the source model. Example: The natural sequence of positive integers (1, 2, ...,
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th terms of the sequences holds is cofinite when and only when φ holds in the source model, and its complement, the agreement set for ¬φ is cofinite iff φ does not hold in the source, and nonfinite sets of indices with nonfinite complements are never
823:, exponential sequences) that make infinitesimals and unlimited elements of what traditional calculus refers to as "higher order" (infinitely smaller or larger) than any polynomial ratio, but they are not essential to actual problems in analysis. 453:
On your more substantial question, I think what's being referred to is the proof of the theorem by induction on formulas. One case of the induction is when the formula being considered is the negation of a simpler formula. That case is trivial if
728:), and (2) it would fall apart as soon as you made the expressive power a little stronger. For example, as soon as you can define the trig functions, you'll have the same problem with the cosine of the element represented by <0,π,2π,3π...: --> 422:(1979, Massachusetts Institute of Technology, republished 2003 by Dover Publications) refers to this theorem as the "fundamental theorem of ultraproducts", and cites Robinson's transfer principle as an application to nonstandard analysis. 473:
I'll take your comment that you've always heard the theorem called "washes theorem" as an approval to change the possessive in the main article, and add a line crediting "fundamental theorem of ultraproducts" to Henle and Kleinberg.
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filters,not just ultrafilters, implying that the use of a free ultrafilter is only needed so that the entire set of sequences can be used in the ultraproduct. Proper subsets of the ultrafilter, including the cofinite filter on
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is the source model (I use the "rational function" sequences of reals to construct a set of hyperreals), allows one to use the cofinite filter, the subset common to all free ultrafilters on the index set, the positive integers
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Just the phrase "fundamental theorem of ultraproducts." Is this single citation sufficient for Knowledge, or should the phrase be removed as insufficiently cited? Are there any other citable uses of this phrase for Łoś's
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and the property of being negative is certainly first-order definable within the real numbers (with plus and times). So consider the element of the ultraproduct represented by the sequence <1, −1, 1, −1, 1, −1, ...: -->
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In fact, honestly, I don't even know how you interpret atomic formulas, if you don't have an ultrafilter. What if the set of indices on which the atomic formula is true is not in the filter, and neither is its complement?
816:). The advantage of using sequences rather than functions of real numbers for a nonstandard model is that it is easier to extend the meanings of standard formulae from the standard model to the nonstandard one. 886:, and there is no sequence induced by a rational function whose square gives you that sequence cofinitely often. You'll have to extend the possible sequences (say, to all functions first-order definable over < 523:
Paraphrasing Henle & Kleinberg, an atomic formula is relation of a finite number of terms, each of which is a particular element, a variable standing for such an element, or a function of a finite number of
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While (as you've alluded to) this isn't really the proper use of this talk page, it's so interesting that I'll indulge myself one more time and make a few more remarks. We should really quit here, though.
502:? All the induction hypothesis tells us, in that case, is that the set of indices for which φ holds is not in the filter. We can't conclude, just from that, that the set of indices for which ¬φ holds, 247:
bothers me. The square brackets suggest we're considering equivalence classes, that is, elements of the ultraproduct, but the text claims that they're elements of the product. I feel like probably
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is proved using this one and the Boolean Ulrafilter Axiom, which is weaker than AOC. It says the Compactness Theorem is equivalent to boolean Ultrafilter Axiom (over ZF) - both are weaker than AOC.
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I still do not see any "negation clause" that requires an ultrafilter. Ultrafilters are only needed for cases where nonfinite agreement sets have nonfinite complements, as in this sequence.
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I should give credit to Eric Schecter's page on defining the real numbers as my source for the "rational functions" as an example of a field with infinitesimals. Go to
1080: 687:. He told me by email that he was introduced to the idea by fellow mathematicians a few years earlier at a meeting, but he no longer had the names of his sources. 1095: 1034: 946:"the axiom of choice is needed at the existential quantifier step" The ultrafilter lemma suffices and is, in ZF, strictly weaker than the axiom of choice. --- 35: 885:
Rational functions aren't actually going to do it. For example, you need to be able to take the square root of the element represented by <0,1,2,...: -->
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then N\A=B and N\B=A, therefore A and B are not cofinite and therefore A and N\A are not in F and therefore F is not an ultrafilter but simply a filter.
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If "Łoś" is pronounced "wash", shouldn't the possessive be "Łoś's"? I propose that this section be renamed "Łoś's fundamental theorem of ultraproducts".
141: 878:"Rational function" is completely standard terminology and is not ambiguous. It's rarely a good idea to reinvent the wheel on nomenclature just because 796:) = √2 is a "rational function" even though it's an irrational number.) A "polynomial ratio sequence" is a sequence derived from such a function, say 1075: 447:
Hm, interesting point. I always hear it called "washes theorem" but it seems to me that I rarely see the apostrophe-ess in print. I don't know why. --
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of that Boolean algebra. That will require a harder and more delicate argument than I think you've come to terms with (if, that is, it's even true).
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However: (1) the proof would be somewhat involved, as it would rely on the limited expressive power of first-order logic in that structure (e.g.
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unlikely to work, it's not impossible that the mathematics as a whole will work, and it does sound like a fun question to investigate. --
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On to negations: Suppose we know the theorem holds for a formula φ and we want to show it holds for ¬φ. Your argument works fine if φ is
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let F={cofinite subsets of N}={A in N such that N\A is finite} when N is the set of natural numbers and N\A={n in N and not in A}
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I use "polynomial ratio" as an alternative name for "rational function" to avoid confusing these functions with functions from
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So I'm not too sure what you mean by "polynomial ratio sequences". Do you mean that the sequence can only be of the form <
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Good luck with your research! While your hope of using this to simplify the introduction to calculus is in my opinion
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I'm quite rusty, but, it seems to me AOC is not required. Only requires that U be a set closed for contain. The
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The reason you don't see any problem with the "negation" step of the induction is that you're effectively
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on Knowledge. If you would like to participate, please visit the project page, where you can join
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is a rational function? That might possibly work, for the specific case of the structure <
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the fact that all functions first-order definable over the structure are rational functions
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There's nothing wrong with the statement. It does not state that the ultrafilter contains
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discussion group on this topic that would be more suitable than these discussion pages?
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oops--that's not actually a "fact"; you can define the square-root function, for example
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But that is wrong, since a filter containing all cofinite sets is not an ultrafilter:
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let A be the subset of even natural numbers and B the subset of odd natural numbers,
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an ultrafilter -- it's just that it's not an ultrafilter on the Boolean algebra of
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is an ultrafilter (and not just a filter) is used in the negation clause, and the
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They present an inductive proof on first order formulas that uses properties of
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cofinite sets. The ultrafiter can (and indeed must) contain also other sets. —
1056: 996: 947: 90: 955: 941: 441: 1002: 984: 920: 849: 736: 691: 635: 624: 572: 514: 478: 462: 407: 397: 729:. So it seems rather limiting as a way of introducing the calculus. 564:
a first order property within the reals. (I'm not even sure that "
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Ultraproduct models of the hyperreals numbers contain sequences (
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The following statement is in the proof, I think it is wrong:
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Still, it does seem like an interesting avenue to explore. --
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can think of another possible meaning of the standard term.
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http://www.math.vanderbilt.edu/~schectex/courses/thereals/
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is an integer" is first order within the real numbers!)
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Limiting the set of sequences in the constructed model
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is an ultrafilter, but otherwise probably hopeless. --
1022: 718:. At least I don't immediately know a counterexample. 317: 253: 179: 112:, a collaborative effort to improve the coverage of 1028: 385: 303: 239: 1091:Knowledge level-5 vital articles in Mathematics 1040:is needed at the existential quantifier step. 654:The sequence <1, −1, 1, −1, 1, −1, ...: --> 1009:Wrong statement in the proof of Los's Theorem 8: 543:im my case. The agreement set of indices 483:Last things first: You mean crediting the 386:{\displaystyle ,\ldots ,\in \prod M_{i}/U} 58: 1021: 418:James M. Henle and Eugene M. Kleinberg's 375: 369: 350: 325: 316: 286: 261: 252: 231: 212: 187: 178: 965:In the examples section, this is stated: 240:{\displaystyle ,\ldots ,\in \prod M_{i}} 1081:Knowledge vital articles in Mathematics 60: 19: 547:for which the formula φ holds for the 498:in the ultraproduct. But what if it's 1096:C-Class vital articles in Mathematics 506:in the filter, which is what we need. 393:was meant instead. Can you verify? - 7: 631:. Is it negative, or nonnegative? -- 106:This article is within the scope of 49:It is of interest to the following 961:Hyperreal example - bad statement? 581:is an integer" is equivalent to "∃ 173:The notation used in the equation 14: 1106:Low-priority mathematics articles 126:Knowledge:WikiProject Mathematics 1076:Knowledge level-5 vital articles 129:Template:WikiProject Mathematics 93: 83: 62: 29: 20: 146:This article has been rated as 1086:C-Class level-5 vital articles 356: 343: 331: 318: 304:{\displaystyle ,\ldots ,\in M} 292: 279: 267: 254: 218: 205: 193: 180: 1: 120:and see a list of open tasks. 1101:C-Class mathematics articles 1122: 788:. (The constant function 408:17:26, 11 April 2006 (UTC) 403:Good catch. I fixed it. -- 398:16:54, 11 April 2006 (UTC) 1003:16:00, 16 June 2009 (UTC) 985:15:54, 16 June 2009 (UTC) 515:20:30, 30 June 2007 (UTC) 479:20:12, 30 June 2007 (UTC) 463:06:04, 30 June 2007 (UTC) 442:05:23, 30 June 2007 (UTC) 145: 78: 57: 1057:02:58, 24 May 2020 (UTC) 942:02:10, 1 July 2007 (UTC) 921:01:27, 4 July 2007 (UTC) 850:18:16, 3 July 2007 (UTC) 737:17:44, 2 July 2007 (UTC) 692:09:49, 2 July 2007 (UTC) 683:and search the file for 636:10:35, 1 July 2007 (UTC) 625:08:19, 1 July 2007 (UTC) 573:00:13, 1 July 2007 (UTC) 152:project's priority scale 1008: 956:18:47, 2 May 2012 (UTC) 169:Product or ultraproduct 109:WikiProject Mathematics 1071:C-Class vital articles 1030: 420:Infinitesimal Calculus 413: 387: 305: 241: 1031: 487:to them, or just the 388: 306: 242: 36:level-5 vital article 1020: 315: 251: 177: 132:mathematics articles 1045:Compactness theorem 1026: 383: 301: 237: 101:Mathematics portal 45:content assessment 1029:{\displaystyle U} 727: 166: 165: 162: 161: 158: 157: 1113: 1035: 1033: 1032: 1027: 725: 392: 390: 389: 384: 379: 374: 373: 355: 354: 330: 329: 310: 308: 307: 302: 291: 290: 266: 265: 246: 244: 243: 238: 236: 235: 217: 216: 192: 191: 134: 133: 130: 127: 124: 103: 98: 97: 87: 80: 79: 74: 66: 59: 42: 33: 32: 25: 24: 16: 1121: 1120: 1116: 1115: 1114: 1112: 1111: 1110: 1061: 1060: 1038:axiom of choice 1018: 1017: 1011: 963: 532: 416: 365: 346: 321: 313: 312: 282: 257: 249: 248: 227: 208: 183: 175: 174: 171: 131: 128: 125: 122: 121: 99: 92: 72: 43:on Knowledge's 40: 30: 12: 11: 5: 1119: 1117: 1109: 1108: 1103: 1098: 1093: 1088: 1083: 1078: 1073: 1063: 1062: 1025: 1016:The fact that 1010: 1007: 1006: 1005: 987: 974: 972: 970: 968: 966: 962: 959: 939:Alan R. 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lethe
16:54, 11 April 2006 (UTC)
Trovatore
17:26, 11 April 2006 (UTC)
Alan R. Fisher
05:23, 30 June 2007 (UTC)
Trovatore
Trovatore
06:04, 30 June 2007 (UTC)
Alan R. Fisher
20:12, 30 June 2007 (UTC)
Trovatore
20:30, 30 June 2007 (UTC)
Alan R. Fisher
00:13, 1 July 2007 (UTC)
Alan R. Fisher

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