User talk:Double sharp/Archive 7

2015:(rather than [6/2} as I do) does not always work: In my system if you truncate a double coincident triangle ²3 (t{3/2}) or the star of david {6/2}, you get the same result ie a double coincident hexagon ²6, the value of which is 6, double that of either of the starting points with value 3 In Grünbaum's system if you are truncating the double triangle {6/2} or the star of david 2{3/1} respectively you also get the same result, a double coincident hexagon which is in that system {12/2}, and not in any way 2{6/1} as perhaps a truncated star of david should be if one doubles the numerator? Now as a rule working with the polyhedra and tilings we do not get to truncate double coincident polygons as they are already truncations, so should not the preferable numbering system be the one that works for truncating the star of david and other even denominator polygons, so that we do not get the anomolous result t2{3/1} = {12/2} in Grünbaum (t{6/2} = ²6 in my system) Something to think about I have also had a look at your Schwarz Triangle page this all started with and there are still mistakes, in particular two which I corrected before doing the double polygon insertions (you seem to have reverted it to your earlier version with the mistakes) plus a number of others which at some point I will list in more detail 1585:

Schläfli symbol?; In the examples you give of odd denominator polygons, truncation doubles the numerator, so that effectively the value of the fraction within the brackets is doubled and the symmetry of the truncated polygon is apparent For even denominator polygons Grunbaum's system does the same with the numerator, implying extra vertices, which are not there as in fact they have actually been doubled up; My system also doubles the value inside the brackets, but by halving the denominator, which can always be done to an even number and leaves you a result that reflects the symmetry of the polygon produced by the truncation; (double is indicated by the superscript 2 before the number, which has no algebraic function, which is why I put it there, rather than after the number!)

2657: 2433: 2482: 1522:

intermediate truncations. Although completely analogous to their icosahedral cousins, these are all generally dismissed as mere compounds but all include the crossed digon face that I call {4/2}, which can be regarded as either the first inscription or first stellation of a square. Treating this as a face in its own right allows it to be regarded as the glue that binds the compounded solids together and I can see no reason to call this face by Grünbaum’s name, 2{2}, since it possesses fourfold symmetry.

1141: 2549: 1651:

such extra truncating edges has to be done by forming the triangles you describe outside the original one, rather than inside as for the normal truncation; simply growing them this way they can never be equalised in length, however equalising them by shrinking the original truncated edges allows equality to be reached in the form of a double triangle with alternating truncated and truncating edges as you go round (each double edge has one of each present)

2598: 2754: 31: 609:; unfortunately, it seems like we'll have to go through a RfC), I'd love you to go check it, see what's wrong, correct grammar if necessary. I've written about it on the project's talkpage, no one reacted :( (I think because I forgot to ping everyone, and changes to our WT:ELEM page happen very often nowadays, so nobody saw the moment when it was the latest change). I hope you can help me bring some attention, could you?-- 1674:, although an accident of geometry happens to make t{3/2} look degenerate. That would also kind of explain t{3/2}'s lack of apparent sixfold symmetry, as t{4/3} is a fourfold-symmetric subsymmetric construction of the octagram (which of course naturally has eightfold symmetry). The inability to realize {6/2} with sixfold symmetry is odd, though, and makes me think that there may be something deeper going on here. 3949: 3255: 2643: 2532: 2449: 1233: 2515: 3740: 3626: 3209: 3150: 2890: 1408: 180: 2628: 2613: 2498: 2466: 2583: 2568: 3878: 2781: 4330: 3783: 2933: 1731: 4232: 3689: 3472: 3099: 3044: 2839: 1357: 129: 2242: 805:

are visited twice: and the resulting polygon is two coincident pentagons. Klitzing makes this clear on his website, when he says that {6/2} is a "doubly wound hexagon that looks like a single triangle": this can only be 3. He explicitly states that it "does not mark the Star of David" (two triangles out of phase with each other, the

1915: 2030:

You raise a good point. Maybe the difference is that t(2{3}) contains two disconnected {6}, because the two {3}'s are initially disconnected, and in t{6/2} the two apparent {6} are connected? So that in the first case you get two hexagons ABCDEF and GHIJKL, where A = G, B = H, etc., and in the second

1650:

For an inverse triangle {3/2}, the edges follow on from each other in reverse direction, but the external angle is 240 degrees if measured in the same direction as originally; Thus its truncation has six edges which have an external angle of 120 degrees, the same as for a normal triangle; inserting

1584:

OK with 2{6/2}, which is not very different to "26/2" (the doubling implied here is different: Grunbaum's sets a pair of coincident triangles out of phase with another coincident pair, my system makes coincident two sets of already out of phase triangles) The point here is probably what counts as the

1548:

What you say makes a lot of sense. The one point I am not quite comfortable with, however, is your choosing the call t{3/2} "3". This breaks the rule that truncating a polygon doubles its Schläfli symbol, viz. t{3} = {6}, t{4/3} = {8/3}, t{5/3} = {10/3}, t{7/3} = {14/3}. Nevertheless you raise a good

1525:

There are also analogous families in the field of tilings, where the (3 2 6) Möbius triangle can be doubled up to produce (3 3 6/2) and indeed trebled to produce (6 2 6/2), all with consistent results parallel to the icosahedral examples, but now set in the plane. The {6/2} these imply is definitely

1006:

I've been meaning to do this rerating for a while. I'm starting from the end and working toward the beginning. I'll try to be very harsh when an article is lacking in an area, like citations. A-class would be granted by comparing with already A-class articles, or by just seeing if it's comprehensive.

919:

A double 'Star of David' is just that, two coincident Stars of David, four triangles in total, two in phase, two out, and thus difficult to put into your terminology, but it is the natural result of truncating a {6/4} ( 2{3/2} in your system?), which is the inverse of {6/2} in my terminology, 2{3} in

849:

Not sure how to resolve this, but the difficulty is that your way takes the {n/d} name away from every case of compound polygon where both n and d are even, so that we have a set of polygons that do not have a nomenclature, and note that this is not every compound as 6/3, 9/3, 12,3 etc. or any others

1918:

book, which says that Ra melts at 700°C and volatilizes at 960°C. Still doing some reading on the matter. But in general for elements beyond Bi you seem to get different values for fundamental properties depending on who you read. I stumbled into this situation for Np as well. Ah well. Probably best

1517:

Indeed stellation is the process that occurs when one takes an icosahedral Möbius triangle (3 2 5) and doubles it up to produce the Schwarz triangle (3 3 5/2), or even trebles it to produce (5 2 5/2), producing star polyhedron families with densities of 2 and 3 respectively, but both involving {5/2}

1497:

My derivation of symbols for the various polygons is based on {n/d} representing a series of n equidistant points arranged in a circle, a polygon being produced by placing an edge from each of these to the dth next one around that circle. Thus in this system a {6/2} is a ‘Star of David’, comprising

960:

Ah, OK, so the 2{2} faces act as "glue" in the same way the digon faces generated by the Wythoff construction for non-compound polyhedra act as "glue", right? Thank you: I learned something new and very cool! I'd like to know some more: can the other regular compounds (5 or 10 tetrahedra, 5 cubes, 5

857:

This last schwarz triangle requires the 'star of david' as a face in these double tilings, along with its truncation the double hexagon, which you would call 12/2, and its inverse which I would call {6/4} and the inverse truncation, which to me is a double 'star of david', that you would call 12/4:

771:

I do not want to start what I believe is known as a Knowledge (XXG) War, so I will not attempt to edit out your work, but simply hope you can perhaps appreciate that I might have a point: the version I spent most of yesterday editing to make what I consider is a correct presentation of this material

665:

for an example: first RM was 2-1, moved. Then others complained a bit later, once it was moved. So it shows that the original 2-1 not-quite-a-consensus was not a representative sample of the community, and so it was later reverted after a long discussion.) So I think that my earlier action should be

644:

About the period 1's: I disagree that the rants by Nergaal can count as a disagree argument (I read not one sentence of substance). Also ththat page was not the place to discuss. And this is rewarding the distractions by that same editor, instead of channeling a talk. And when "there is no consensus

412:

And also, it seemed very unlikely to me that it could ever describe the period instead of two individuals, because H is certainly the most oddball element on the periodic table, and there's not much to talk about periodic trends if there are only 2 elements. (For the periods further down, the trends

2687:

for brainstorming on how next year's WikiCup competition should work. Please come along and share your thoughts- What works? What doesn't work? What needs changing? Signups for next year's competition will be open soon; we will be in touch. If, at this stage of the competition, you are keen to help

2014:

sorry not to have been back for a while, but busy on another project I have however been having a look at the results from truncating various polygons in more detail and find that the rule of doubling the numerator you and Grünbaum apply and use as the reasoning for calling the star of david 2{3/1}

1602:

I dunno about whether the doubled vertices are still there. I always thought of {6/2} (Grünbaum's notation is used in this post) as having six vertices, conicident in pairs: so that if you called it ABCDEF (vertex naming), the coincident pairs would be AD, BE, and CF. I suppose you could picture it

853:

My main difficulty however is that when a mobius triangle is doubled up to form the basis for mainly double versions, it works in the polyhedra for (3 3 3/2), (5 5 3/2), (3 3 5/2), (4 4 3/2) and in my view for (3 3 4/2), but when we come to the tilings and try (6 6 3/2) it works, but (3 3 6/2) does

767:

You have referred me back to 'refs', which I have not looked at as yet, but they are likely to be wrong as this error goes right back to one that the great Professor Coxeter made in his famous 1953 Uniform polyhedra paper, where he dismissed as non-uniform any polyhedron requiring the truncation of

504:

page was not that substantial. More of a bad listing. So for that reason alone, we could have pulled the GA status from that page. And without GA, the page looses its right to form a FT, and this FT would have ceased to be. Had we done that route, the FT status would not have helped the page either

221:

That's awesome Neptunium passed its GA! Thanks for all the work you put into it and for dealing with the nomination process. I'm sorry I haven't been on lately, I've been crazy busy in real life and it looks like it's probably going to be that way for a while unfortunately (like probably through at

4291:

I must admit that I'd approach the rewriting task with some trepidation – Greenwood and Earnshaw after all splits off discussion of O and S from the rest of the group, and while Hollemann and Wiberg keep them all in one chapter they put the elements in different subsections that almost behave like

1913:

Yes, I know about this discrepancy. Kirby basically throws up his hands and writes that it is either 700°C or 960°C. I do not know which is right. The CRC quotes 700, but I do not really trust them for rare radioactive elements (e.g. their Ac value is also wrong, or at least outdated, according to

1501:

The derivation adopted by Grünbaum is different, but also involves n points in a circle, but each edge towards the dth next one is placed in turn, starting from where the last one finished. In this system {6/2} is a pair of coincident triangles that share vertices and edges and only half of the n

804:

However the modern usage of {10/2} is what you call 5: it means that you start with one vertex, join it to the second one after, and then repeat the process with the vertex you are now on until you have drawn ten edges. This means that half the original vertices are not visited, and the other half

751:

I see a polygon's number defined as n/d, where n is the number of vertices and d the number of the next vertex one visits to form the polygon's edges: for instance 5/2 has five vertices and one visits every second vertex to form the pentagram; similarly 5/3, its inverse is formed by visiting every

845:

If you start at one vertex and then follow on around the requisite number of vertices repeating serially the operation of say going to the second next vertex, you do indeed trace out a double polygon, leaving every other vertex out of the picture; However if you start at every vertex at the same

1509:

My derivation of {6/2} as the symbol for the Star of David also relates to the process of inscription, as within every polygon there are layers of internal edges to be found that run between non-adjacent vertices of the external polygon, say {x}, so that {x/2} is the first inscription, {x/3} the

601:

Re neptunium. As I said, that would happen after the FAC is over. It's slowly coming to its end, I think, and I'll try to start the review after that. But I must say: if I haven't finished by the end of the first decade of august, it'll have to wait until late September or even October :( Really

1646:

Normal truncation can be seen as the insertion of a new edge halving the external angle of the original polygon, the truncating edge being grown until all the edges, both truncated and truncating alternately, are equal in length; For a triangle {3}, that external angle is 120 degrees, which is

1529:

Going beyond these and into the realms of quasitruncation, there are tilings that require a truncated {6/4} to be incorporated. In my system this is a {2^6/2} and comprises four triangles overlaid, two coincident pairs out of phase with each other, or alternatively an overlaid pair of Stars of

763:

Physically taking a 5/2 pentagram and cutting its corners off, one arrives at a point where the truncated edge is the same length as the truncating edge, as one would with a normal polygon being truncated, and this is simply a double coincident pentagon, not a 10/2; A double pentagon is what is

2688:

the with the WikiCup, please do what you can to participate in review processes. Our finalists will find things much easier if the backlogs at good article candidates, featured article candidates, featured picture candidates and the rest are kept at a minimum. As ever, questions are welcome on

1521:

This process has analogues in the world of octahedral symmetry where the (3 3 4/2) Schwarz triangle produces a 2-dense family that includes polyhedra such as the Stella Octangula, 3| 4/2 3, and the 3-dense (4 2 4/2) family is that of the cross polyhedra {4,4/2} and {4/2,4}, along with their

915:

I can see how your nomenclature works now you have explained that what I call {9/3} is your 3{3}, but was this necessary to change to have the term {9/3} available for a triple triangle, three coincident, that does not arise in the normal course of events, whereas double ones do result from

796:

Like I said, it's because the meaning has changed. The modern interpretation of {10/2} is actually what you mean by a truncated 5/2, and looks exactly like a double pentagon. I think this is because others (e.g. B. Grünbaum) have also realized that Coxeter made a mistake here, but (perhaps

716:

It's purely procedural: I can't really vote for the topic to be delisted, since the lead article is back and its GA status has not (yet) been revoked. If and when that happens, I will vote for delisting. On that page we are voting about removing the topic's FT status, not whether the

4047:

article you edited some time ago; I've given it another look and I think it only needs a few last touches (well, apart from things like prose review and refs checks, I'm not to judge that) before it can be nominated, being closest to FAC of any articles you want to feature. Are you

2034:

Please list the mistakes! I tried to follow the sources listed at the bottom of the article, but I don't rule out having made typos. If the sources have made mistakes, and you've published an article giving corrected figures, feel free to put in the figures and cite your articles.

1619:→ ∞. In both limiting cases, the cases just before them have noncoincident vertices: so maybe there really are two vertices, that are just in the same place. Of course if you go in the negative direction, you first get triangles dangling off the original triangle, which shrinks as 669:

I see two options here: either start a GAR, or try to fix it ourselves first. R8R Gtrs has stated how he thinks it can be done: we would do well to listen to him. What he says has substance, and he explains how he would make it a good article. But the article title should still be

759:

The result of truncating a 5/2, however, whilst also comprising two pentagons, has them coincident, so that the ten theoretical vertices are arranged in five pairs, the edges are doubled up and indeed so are the faces, hence the concept of a double pentagon for this phenomenon

4292:

separate chapters! But it seems that we have to now. I think a better group for a newcomer to do would be the halogens – that's at least not as easy to mess up, and is one of the first groups typically encountered when beginning chemistry (the other being the alkali metals).

4167:

To add something of substance to this post, here's a list of some notable objects in Corona Borealis that could be useful for the article whenever you decide to write it: Abell 2061, Abell 2065, Abell 2079, Abell 2111, Abell 2124, Abell 2142, Abell 2162, 3C 332, PG 1211+143.

755:

Taking one of our disputed polyhedral examples, my personal view is that a 10/2 has ten vertices and one visits every second one to form the polygon, which thus consists of two pentagons interlocked, but at 180 degrees to each other, maintaining the ten distinct vertices

1060:

I'm not looking at the GAs/FAs in this first round, even though there are some I am not too happy with quality-wise. Those will need a GAR/FARC and I don't immediately have the time to set them up. And honestly for some of them I could try to fix them myself (e.g. Cf).

1505:

In terms of simple symmetry considerations, I think Grünbaum’s choice of symbols is counter-intuitive as the Star of David that he calls 2{3} possesses sixfold rotational symmetry, whilst the double triangle that he calls {6/2} has only threefold rotational symmetry.

222:

least the end of August, maybe longer; not really sure right now) But yeah, when things do calm down again, I'll definitely be up for doing some more element articles if you're not to busy then either. Thanks again for all your help and hard work with the article!

916:

truncating even denominator polygons: a question then arises: what do you call a truncated 3{3}?; to me it is {18/3}, truncation of {9/3}, comprising three out of phase hexagons, so is it 3{6}, leaving your {18/3} symbol to describe three coincident hexagons?

4287:

Since further GAR seems likely to be unproductive it appears that we will have to completely rewrite the article in a better way. The tagging should make it clear to readers in the meantime that the content that is currently there has many shortcomings and

945:

Yes, you got the specifics of "my" (actually Grünbaum's, I think) system correct. I think the use of {9/3} had to be changed so that all fractions would work the same way. It would look odd and inconsistent to have {12/2} and {12/3} work differently, for

884:: e.g. {9/3} traces three coincident triangles in Grünbaum's nomenclature. The compounds have nomenclature as well: the Star of David is 2{3} or {{3}}, the Star of Goliath (Coxeter's {9/3}) is 3{3}, and two out-of-phase pentagrams are 2{5/2} or {{5/2}}. 4269:. A disappointing outcome but undeterred I have marked up chalcogen with missing and dubious flags to highlight the shortcomings and mistakes, currently I am ill so have had some internet time available. The more I read it the worse the article gets! 1669:

But if the vertex count has doubled when truncating {4/3}, then I don't see why it shouldn't do the same when truncating {3/2}. Maybe this is a false analogy and I am mistaken, but at first glance I would expect both cases to behave the same way as

861:

The simplest of these to imagine is 3 6/2 |3 which has a vertex with two hexagons, a triangle and a star of david producing a double covering of the plane: what do I now call that star of david if you have taken the 6/2 name for a double triangle?

1513:

This is essentially the same process as that of stellation, which occurs outside a polygon, where edges are extended to produce a similar series of polygons: {x/2} formed at the first crossing of extended edges, {x/3} at the next and so on again.

797:

unfortunately) decided to correct him by reassigning his terminology to the correct figures. I agree with you that the truncation can always be done, although it sometimes produces degenerate figures like {10/2} with coincident vertices and edges.

660:

Even if you don't count Nergaal, there is stil R8R's statements: given that only 3 supported, there is no consensus, I think. (Even at 3-1, I would revert to the previous status and discuss, even if the change had been done while it was 3-0. See

2110:

Great! Thank you so very much! I have had difficulties finding an editor willing to do so. By the way, do you happen to also speak Greek? If not, do you know any editor who will agree to translate a short article from the Greek Knowledge (XXG)?

812:

The Grünbaumian terminology has the advantage that it means that the rule that truncating a polygon doubles its Schläfli symbol always holds, even if the denominator is an even number. So a truncated pentagram {5/2} forms a doubled pentagon

439:

Key for the Featured topics nomination status seems to be the GA status of the article (now a redirect). That could have been reduced some steps with reason as described now, and so pull the FT ground (it just happened to join two FA's).

898:

this way, for example? (Schläfli symbol 2{3,3}.) In your example the angle defined by 6/2 is 2π/6: wouldn't that trace the same way as π/3, but twice? Then how does 2{3} get into it? I'm confused: could you explain again what you meant?

2443:), a WikiCup newcomer, finished top of Pool A and was the round's highest scorer. Godot is a featured picture specialist, claiming large numbers of points due to high-quality scans of historical documents, especially banknotes. 800:

Coxeter's usage of {10/2}, which is incorrect, is that you take every vertex of a decagon and connect it to the second one after it. This, as you say, traces the two-pentagon compound, with the pentagons out of phase by 180

521: 2560:), the fourth and final wildcard, has participated in previous WikiCups, but not reached any finals. Bloom's points are mostly thanks to did you knows, featured lists and good articles related to sport and national symbols. 1035:

I did the same years ago. It is fun to compare and to evaluate. My problem was I had to do it two times because in the first run I was to critical to the end and to friendly in the beginning. Good luck for the 120 elements

1890:

Hi, I had a longer search for the melting point of radium. The 700°C are 1910s work from one of the Curies, I think. There might be a better source from Kirby. If this is really 700°C or 960°C we should state this

823:

If this was too long and unclear, I hope this makes the above clearer: yes, truncating a pentagram leads to a double pentagon, which is the current meaning of {10/2}, not the non-coincident 2-pentagon compound.

923:

You ask about the stella octangula which to me is simply derived from a Schwarz triangle as 3| 4/2 3, the {4/2} faces ( 2{2} in your terminology) being the glue that binds the two tetrahedra together

4265:

Thanks for your efforts. I apologise for not being able to get involved but there has been a death in the close family and the aftermath is taking a lot my time. My comments on the reassessment are

2621: 2331:' article (as these thing can only be done by registered users) yet he seems too busy at the moment. Do you mind sparing several more minutes of your time to do so? It would be highly appreciated! 842:

I have had a look at your reasoning for calling the double polygons with which we are concerned 6/2, 10/2 and 10/4 and can see that it all depends on how you define the polygon in the first place:

748:

It is strange not knowing who or where you are, but it seems we have a fundamental disagreement over how to truncate even denominator polygons, as is required to construct a number of polyhedra

1075:

P.S. Due to lack of time I may pause it halfway and then continue tomorrow, perhaps somewhere around element 40 or 50. I could get here so quickly because so much of periods 6 and 7 is GA/FA.

2540: 2606: 2489: 3816: 624:

I'll take a look. But I think you should write more about how a periodic table cell should look like for an unnamed element, like E113 (we discussed this before: it is unclear otherwise).

2636: 2460:) is a WikiCup veteran, having been a finalist every year since 2010. In the semi-final, he was Pool B's highest scorer. Cas's points primarily come from articles on the natural sciences. 1654:

A similar process with external triangles will work for any inverse polygon and is quite instructive in getting from an inverse square {4/3} to its truncation the octagram {8/3}; Enjoy

1057:

Thank you for your good wishes. I'll try to be consistently nasty, because in my experience a C→FA is felt as more glamorous than B→FA or GA→FA (I've never seen anyone do the last one).

2506: 1549:

point that t{3/2} doesn't have sixfold symmetry, which 2{3} does. I wonder why there is this conflict between attempting to extend both rules. There must be an interesting story here.

1494:

You seem a bit busy with radioactive elements at present so I have taken the opportunity to collect my own thoughts and summarise these matters from my own particular point of view:

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by Branko Grünbaum: p.466 shows diagrams of the polygons that in the modern usage are symbolized {6/0}, {6/1}, {6/2}, and {6/3}. {6/2} is exactly what you call 3 in this terminology.

2457: 2674:

will run through September, and revolves around expanding stub articles, especially high-importance or old stubs. In addition, a proposal has been made for a new competition, the

2031:

case you get a dodecagon ABCDEFGHIJKL. Well, in Grünbaum's nomenclature the doubling rule seems to hold for all symbols in the form {x/y}, but not in the form x{y}: is that true?

764:

actually shown on all the illustrations of the polyhedra, where although you list a 10/2, I cannot find any such polygon consisting of two interlocked but out of phase pentagons

2440: 253:, but they'll have to wait for some time. (Fl will definitely be first: I'm almost done, with one section not yet rewritten. Th and Fe will take a considerable amount of time.) 2492:) was Pool B's runner-up. Another featured picture specialist, many of Adam's points come from the restoration of historical media. He has been a WikiCup finalist twice before. 3812: 2651: 2526:) is the second wildcard. George's points come primarily from meteorology-related articles. This year and last year, George was the first person in the competition to score. 2509:) won the WikiCup in 2012 and 2013, and enters this final as the first wildcard. She focuses on biology-related articles, and has worked on several high-importance articles. 677:

I think what we should do is divide them not into individual elements (except maybe period 1), but instead into blocks, and not discuss individual elements one-by-one. See

4266: 2474: 2767: 768:

an even denominator polygon; This does not mean that the truncation cannot be done, he simply did not know how to handle it using the concept of the double polygon

602:

sorry, but I have real difficulties to go through. (I don't think such a situation will happen, though, the end of the FAC is near (I think) but have that in mind)

4337:, but there are some minor changes or clarifications needing to be addressed. If these are fixed within 7 days, the article will pass; otherwise it may fail. See 485: 345: 3991: 2794: 2675: 926:

I would like now to insert an illustration showing 3 6/2 |3, but cannot work out how as this system seems to take text only; If you would care to email me at

390:

Yes, we can understand that as a consensus. About featured topic: as Double sharp remarked, the article was low in quality. It did not actually describe the

3532: 1968: 1830: 1464: 555: 3807: 1283: 4014:

if the total is over 5,000. Finally, if you know of an interesting fact from another recently created article, then please feel free to suggest it on the

3320:

if the total is over 5,000. Finally, if you know of an interesting fact from another recently created article, then please feel free to suggest it on the

1306:

if the total is over 5,000. Finally, if you know of an interesting fact from another recently created article, then please feel free to suggest it on the

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with "triangles" alternating between being {3} and {6/2}. I don't think compounds can be truly generated with Schwarz triangles – how does one make a

3747:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

3633:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

3216:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

3157:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

2897:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

2481: 1415:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

606: 187:

for comments about the article. Well done! If the article has not already been on the main page as an "In the news" or "Did you know" item, you can

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P.S. I haven't forgotten about your request; but unfortunately have been more busy than I would like to be! I think I can do it tomorrow, though.

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a stellated hexagon, the Star of David polygon with its six distinct vertices and sixfold symmetry, rather than a double coincident triangle.

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relatively short article from the French Knowledge (XXG) in order to create an equivalent entry here on the English Knowledge (XXG)? Thanks!

1964: 1826: 1460: 551: 4324: 3734: 3620: 3203: 3144: 2957: 2884: 1402: 174: 4177: 2678:, which the organisers plan to run next year. This competition is based on the WikiCup and aims to reduce the good article review backlog. 2374: 2360: 2332: 2306: 2292: 2264: 2226: 2204: 2176: 2148: 2112: 2078: 662: 4011: 3317: 2695: 2427:

The final of the 2014 WikiCup begins in a few short minutes! Our eight finalists are listed below, along with their placement in Round 4:

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points get visited at all. It is this double triangle, the natural result of truncating the inverse triangle {3/2}, which I call {2^3}.

2477:) was Pool A's runner-up. Czar's points come mostly from content related to independent video games, including both articles and topics. 1531: 3521:

Hi. Thank you for your recent edits. Knowledge (XXG) appreciates your help. We noticed though that you've added some links pointing to

2543:), the third wildcard, was the 2010 champion and a finalist last year. His writes mostly on military history, especially naval history. 1819:

Hi. Thank you for your recent edits. Knowledge (XXG) appreciates your help. We noticed though that you've added some links pointing to

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I know, right? I took a look through and found problems too, but you beat me to most of them. ;-) I did join in the tagging, though.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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Thanks for the list! I'll probably do it when I don't feel like working on an element, though. Probably after I'm done with Ra.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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There are two upcoming competitions unrelated to the WikiCup which may be of interest to those who receive this newsletter. The

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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agreed (and in fact proposed this earlier, but didn't carry it out for period 1 because it was a GA), and after some discussion

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This process may take up to 7 days. Feel free to contact me with any questions or comments you might have during this period.

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Now I'm confused. Is a double Star of David supposed to mean two coincident Stars of David? I would call that 2{6/2}, I think.

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decreases. Somewhere along this line I think you get {6/2}. Or have I just rediscovered quasi-, hyper-, and antitruncation?

2667:) have all performed well to reach this stage of the competition, and we hope they will all be joining us again next year. 3955: 3261: 1694:

Duue to a recent (yesterday) bereavement I will have only limited time to give to wikipedia so I am posting a wikibreak.

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David. This again has sixfold symmetry and I am not sure whether Grünbaum’s system can cope with it in a sensible way?

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star of david face (2{3}) and some quasitruncations including the double star face: 6/4 2 6| is one of the simpler ones

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is not lost, as it sits two down the list below your 'corrections' and can easily be reinstated if you are in agreement

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Changing your !vote AFTERWARDS because the outcome has changed? Why would I spend time on this? Why reasoning at all? -

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are either largely the same or are distinct enough in various sections that they should go to their own articles, e.g.

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My intention is to discuss this with you further and reach common ground, so I trust you will respond in similar vein

4109:] you deleted yout earlier, 16:12 post. Was that intentional so we forget, or would you keep it (so I can respond)? - 3522: 1820: 344:

I noticed that you redirected articles on the Period elements. This includes Period 1, which is the lead article in

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Hi. Thank you for your recent edits. Knowledge (XXG) appreciates your help. We noticed though that when you edited

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Hi. Thank you for your recent edits. Knowledge (XXG) appreciates your help. We noticed though that when you edited

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Hi. Thank you for your recent edits. Knowledge (XXG) appreciates your help. We noticed though that when you edited

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to just state in the article that it melts at either 700 or 960°C and then have a note explaining the situation.

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LOL, yeah. Give me enough protons and neutrons to make Pb, then we'll have a great source of virtual pions! XD

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Not intentional at all, actually – I managed to edit-conflict with myself again... it's back now, hopefully.

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has been reviewed, and some issues with it may need to be clarified. Please review the comment(s) underneath

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again to fix it. If I misunderstood what happened, or if you have any questions, you can leave a message on

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Strangely I didn't get a citation error on my screen. Which cite is causing the problem? I'll look into it.

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I did Md. No and Lr should be about as easy, although there would be more to say about history due to the

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How can 3 6/2 | 3 contain Stars of David? Its vertex configuration is 6.6/2.6.3, so it just looks like a

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Polystar, its an anagram (Patrick Taylor, Ipswich UK) not sure about these tildes? have I done it right

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had to seek the permission of the United States government to propose it be named after Russian chemist

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If you wish to start or stop receiving this newsletter, please feel free to add or remove yourself from

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OK, I found it and fixed the link above. I will take a look first and think about it before responding.

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next, and so on going deeper towards the centre and beyond where the inverse polygons are to be found.

348:. So before I take this topic for review, I want to know if there was a consensus to redirect these to 4274: 4162: 2760: 2753: 1789: 1699: 525: 353: 929:

I can email my scan back to you. There are other more complex tilings which also include this {6/2}

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this way as a series of ditrigons, i.e. hexagons whose sides alternate between length 1 and length

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Great :) Then I'll try to check it carefully during this weekend (however, no promises on dates)--

674:, or something similar, to make it clear that the current content has no place in the new article. 4353: 4348: 4247: 4242: 4089: 4053: 3431: 3371: 2803: 2732: 2718: 2536: 2020: 1659: 1592: 1574: 1178: 1158: 934: 870: 783: 614: 4226: 3683: 3466: 3093: 3038: 2833: 1351: 123: 957:. I'd love to see your picture of 3 6/2 | 3 this way, where others can also see it and comment. 4334: 4293: 4191: 4125: 4071: 3925: 3888: 3857: 3842: 3787: 3767: 3708: 3653: 3589: 3578: 3506: 3491: 3413: 3391: 3281: 3232: 3227: 3173: 3168: 3114: 3109: 3059: 3054: 3003: 2988: 2937: 2913: 2908: 2854: 2849: 2789: 2602: 2485: 2346: 2278: 2250: 2190: 2162: 2134: 2097: 2055: 2036: 1995: 1984: 1934: 1920: 1876: 1800: 1710: 1675: 1671: 1643:

I think you are talking about quasitruncation here, i.e. the truncation of an inverse polygon

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Archiving first as older than a month: for continued discussion, you can refer to the link at

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The way I see it A is like FA in comprehensiveness, and GA is like FA in structure and style.

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php?sym=Md 101. Mendelevium - Elementymology & Elements Multidict]. Peter van der Krogt.

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that an edit performed by you may have introduced errors in referencing. It is as follows:

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that an edit performed by you may have introduced errors in referencing. It is as follows:

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Could you please post a message in my talk page once you complete the translation? Thanks!

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any more" that should be an outcome in a more proper way. Anyway, next steps: rm the GA. -

488:. The whole set was three articles together (with H and He). A requirement for FT is that 4222: 3679: 3462: 3089: 3034: 2829: 2073:

I saw you listed yourself as a translator from French. Could you please kindly translate

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You can actually insert illustrations into Knowledge (XXG). Instructions can be found at

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I do not think that worked, but the image is somewhere in commons if you can retrieve it

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It's OK to remove this message. Also, to stop receiving these messages, follow these

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and respond there as soon as possible. Thank you for contributing to Did You Know!

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GT? We need Th, No, and Lr. I can do the last two (each will probably take a week).

4344: 4238: 3895:. If you do not want to continue with the nomination, tag the nomination page with 3763: 3758: 3754: 3739: 3704: 3699: 3695: 3649: 3644: 3640: 3625: 3574: 3570: 3546: 3502: 3487: 3482: 3478: 3223: 3208: 3164: 3149: 3105: 3050: 2904: 2894: 2889: 2845: 2436: 1980: 1976: 1872: 1868: 1844: 1838: 1476: 1472: 1422: 1407: 1363: 1269: 567: 563: 541: 194: 179: 135: 752:

third vertex and effectively going around the same pentagram in reverse direction

1611:= 0 you have a triangle, which is progressively truncated to become a hexagon at 981:

I updated it, and I will try to add your updates on the actinides if you like? --

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It seems to me that the Schwarz triangles favour my way of seeing these polygons

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If you wish to start a new discussion or revive an old one, please do so on the

2050:(Note: due to their being over a month old I archived the previous sections at 1780:

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846:

time and proceed in parallel you get the compound versions, star of david etc.

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Please check this page and fix the errors highlighted. If you think this is a

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Please check this page and fix the errors highlighted. If you think this is a

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Well with all this in mind, I started an FTRC for the topic. It can be found

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Oh, I'm very sorry to hear that. Take as much time as you need off from WP.

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No, I don't speak Greek, but you may have some luck with someone listed in

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