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2^^2=4 is not congruent modulo 10 to 2^^3=16), explaining which is the exact number of stable digits of G (providing also proper peer-reviewed references) and improving the overall quality of the page. Please, let me know if something is not clear or needs further edits. P.S. Still trying to learn how to sign my comments properly. --
798:
Edited the "Rightmost decimal digits" section, fixing some mistakes (i.e., the wrong assumption that any integer tetration of height d should have at least d-1 stable digits, which is false... consequently, I added the trivial example of the base 2 that has d-2 stable digits only, given the fact that
646:
In other words, G is calculated in 64 steps: the first step is to calculate g(0) with four up-arrows between 3s; the second step is to calculate g(1) with g(0) up-arrows between 3s; the third step is to calculate g(2) with g(1) up-arrows between 3s; and so on, until finally calculating G = g(63) with
895:
It can be difficult. The last 3 digits of Graham's number are 387. So multiplying it by 3 and adding 1 will give you a number ending in 162, which is divisible by 2 but not by 4. Then divide it by 2. I can't continue the sequence right now.
652:
Earlier, g(0) is defined as equal to four, so not need to "calculate" it. And the final step is computing g(64) not g(63). Could someone please fix the text? Or the formulae? I'm not sure I want to wade into the dispute at this juncture.
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482:. A part of the service the reader needs to read the reference. When one part of the chain is broken, the ref is broken, so we need the chain, to read the Martin Gardner article. --
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Because often early attempts at notation when the mathematician is still figuring it all out is cumbersome, and more elegant notation is developed later. For example, Newton's
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Numberphile, Dr. Trefor Bazett , Travis
Richardson, a brazilian youtuber called "Ciência Todo Dia" and more, most of the people don't actually mention a number g(0).
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Somebody please put a banner at the top of this talk page with a warning related to this question that I'm sure people will keep asking over and over again.
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No, they can't. This is currently too difficult a problem to calculate. At least, it is too difficult in base 10. In base 3 the answer is 1000000000...
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691:(rather than g(64)) seems to be universal everywhere else. Looks like that got changed in the same revision that shifted the numbering convention by 1.
670:
There are still some other places in the article where there is a similar discrepancy with the stated definition. I'll take a look at addressing that.
384:
The ten rightmost digits of Graham’s number is 2464195387, but what are the ten leftmost digits of Graham’s number? I want to know them like (sequence
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I left the following feedback for the creator/future reviewers while reviewing this article: Please remember to tag redirects that you create per
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I don't really care whether this article uses zero indexing or not, whether is starts with g0 or g1, or whether Graham's number is g63 or g64.
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I've reformatted the reference so now the link in the title points to the archived version rather than to the usurped / dead link. --
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Sorry, but I think that this article can show the leftmost 1000 digits and the rightmost 1000 digits for the Graham’s number.
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instead of function notation g(n). I'll leave making that change to the article as an exercise for the reader. (c:
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Graham's Number is g(64), not g(63), most of the mathematical youtubers can confirm that Graham's Number is g(64)
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Right now, we have the following text that disagrees with the mathematical notation that precedes it:
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be legit, but I can't assess it myself. "Most of the mathematical youtubers" - point to one, please.
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But it needs to be consistent, and hopefully consistent with the body of literature it is based on.
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Knowledge. If you would like to participate, please visit the project page, where you can join
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When a brand new editor makes a change like that without citing a source, it
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notation for calculus - Leibniz's notation is what we use today. Or the
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that uses that notation, or rather it uses subscript notation g
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The number is almost always defined as g(64) instead of g(63).
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Powers of 2 become exponentially rare at large numbers and
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Also, is this just a "start at 0" vs "start at 1" thing?
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Wayback machine's link to the
Scientific American article
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What does Iteror.org have to do with Graham's number?
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Ok. Nobody else stepped up so I made this edit myself.
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Really? I wonder why people use that notation then.
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It is a part of the chain which lies on the path to
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