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1034:) isn't even defined for n less than 2, not to mention it is the wrong expression for the number of undirected edges in a complete graph (and thus number of edges in a tournament). If something else is meant by "edges" or by the given expression, than this should be pointed out. As it stood, it was plain wrong. -- ManDay
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We show that a tournament of any size has a
Hamilton path. Clearly a tournament with 2 nodes has one. We prove that a trournament of any size must have a Hamilton path because if any tournament with n nodes has such a path then any tournament of size n+1 containing the tournament of size n must have
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The diagram in the intro seems to say that the number of edges is "n choose 2", whereas in general it is n*(n-1)/2, the same as K(n). In the case of n=4, these values are the same, but it seems pointless and unhelpful to give the former. I'd be bold and change it if I knew how, though I fear I've
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The graph shown on the right is not transitive (at least not according to the definition given in this article). It says a graph with n vertices should have as score sequence {0, 1, ..., n-1}, which means, every outdegree exists exactly once. Nodes 3 and 4 both have the same outdegree (ie. 4: 3-:
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I believe the exact relation is that the paradoxical tournaments and the transitive tournaments are disjoint from each other: it is not possible for a tournament to be both paradoxical and transitive. However there exist tournaments that are neither paradoxical nor transitive.
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Aren't all tournaments complete graphs? Isn't a complete graph with k vertices always k-connected? Therefore wouldn't it be simpler to write, "Moreover, if the tournament has 4 or more vertices, each pair of vertices can be connected with a
Hamiltonian path (Thomassen 1980)."
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Oops, yes, thanks, and thanks for the reversion. Sloppy pencil & paper work, and brain-softening. Mind you, I think it a bit unkind to call n*(n-1)/2 'random and arbitrary', it is intuitive for the complete graph, and a limiting case of the famous
363:"Every tournament on n vertices has a transitive subtournament on log2n vertices. Reid and Parker showed that this is the best possible result: there exist n-vertex tournaments whose largest transitive subtournament is of size log2n."
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Imagine that a tournament with n nodes has a
Hamilton path. Label the nodes in the path v1, v2, ..., vn. Add another node X to the graph and connect it to all the existing nodes with directed edges. Then there are 3 cases:
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Some of the edges connecting X to the existing graph point from X, while others point to X. Suppose vi is the first node in v1, v2, ... that X points to. Then v1, v2, v(i-1), X, vi, v(i+1), ..., vn is a
Hamiltonian Path.
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Transitive tournaments are the same thing as acyclic tournaments, but they are a special case among all tournaments. This example is not one of these special cases. It is a tournament, but not transitive and not acyclic.
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Sorry for the newbye question, but what is the relationship between a paradoxical tournament and a transitive tournament? My first impression is that a paradoxical tournament is the same as a non-transitive tournament.
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More generally, I think this proof should be written without mathematical notation. It's a fantastic inductive proof because it's so simple, and it would be great to make it accessible to the general public.
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There is no requirement of having an even number. (This is not like an actual sports tournament that has to proceed in rounds, and n choose 2 is meaningful for odd numbers as well as even.) —
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It's a directed form of connectivity. I imagine that it means that it remains strongly connected after the removal of any three vertices, but I'd have to check the source to be sure. —
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It's not n over 2, it's n choose 2. And it's perfectly well defined for n less than 2, equalling zero for those n. And it is always the correct number of edges. There is no mistake. —
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Whatever the exact relation, it would be a good idea to make it explicit in the article, because paradoxical tournaments are explained under the section about transitivity. --
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In addition, no such i exists if all edges between v0 and v1 ... vn point away from v0. (One cannot say that 0 is the biggest such i, because there is no edge v0-: -->
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R. That is, for each x, y in a set E, either x = y, either x R y, either y R x. R can be seen as the domination relation. Would that be worth saying in the article?
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That's really helpful David, thanks. I now see that "n choose 2" is the same as n*(n-1)/2 for all even n - and a tournament must have an even number of players....
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A UCI ICS grad's question fielded by a UCI CS professor on a random obscure
Knowledge Talk page. That's almost a graph theory connectedness anomaly in itself. -
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The article would probably benefit from these sentences, and even better, an example of a tournament that is neither paradoxical nor transitive. --
591:"Many of the important properties of tournaments were first investigated by Landau in order to model dominance relations in flocks of chickens."
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His initials were already given in the references section. Apparently he was Hyman G. Landau, a mathematician at the
University of Chicago. —
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Which example above? I assume the 4-vertices graph drawn on top of the article. If correct, that should be made clear in the article IMHO. --
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It reads: "Moreover, if the tournament is 4‑connected, each pair of vertices can be connected with a
Hamiltonian path (Thomassen 1980)."
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In case it interests you, I made an illustration of the proof of the theorem about
Hamiltonian paths in tournaments. Please notice that
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1 Condition (3) states: T is asyclic. What is the source of that condition, and which one is correct (graph or condition)?
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The intro says the graph is undirected, but the image directly below that statement shows a directed graph. Please fix. --
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I would remove "first", as we have other important results from 1934, that is before 1953, date of Landau's article. --
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This comes with no reference, and is apparently simply wrong. I belive the best known upper bound is ~2log2n.
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I know that the proof needs to found elsewhere to publish this in WP. Sorry, I don't have time to do that.
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All the edges between X and v1, v2, ..., vn point from X. Then X, v1, v2, ..., vn is a
Hamiltonian Path.
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All the edges between X and v1, v2, ..., vn point to X. Then v1, v2, ..., vn, X is a
Hamiltonian Path.
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The group of isomorphisms on any tournament graph is solvable. This should be mentioned somewhere.
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on Knowledge. If you would like to participate, please visit the project page, where you can join
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it has that form rather than just being a random and arbitrary quadratic polynomial. See
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First, it's missing the ground case of n=2, which has a Hamiltonian path by inspection.
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Tournaments can also be defined by means of an irreflexive, antisymmetric and total
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Other topics that might be added include number of non-isomorphic tournaments over
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The first shown graph is stated as being a tournament graph but is cyclic: 1-: -->
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You missed 3 → 8. In fact, the tournament has an extremely simple description:
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to edges of a complete undirected graph, thus making it a directed graph. --
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v0.) Nevertheless, a Hamiltonian path still exists, v0, v1, ..., vn.
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1587:{\displaystyle v_{1},\ldots ,v_{i},v_{0},v_{i+1},\ldots ,v_{n}}
831:"as the above example shows, there might not be such a player"
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Nope, the intro says that a tournament is a graph obtained by
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Nope. I decided not to contribute anymore on WP:en, sorry. --
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Nope. I decided not to contribute anymore on WP:en, sorry. --
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Nope. I decided not to contribute anymore on WP:en, sorry. --
507:. Since < is a linear order, it is clearly transitive.—
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They are always the same. And "n choose 2" describes
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Who is Landau? Can we have a first initial or link?
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1650:) 17:00, 24 June 2017 (UTC) ArthurG
1157:suppose that the statement holds for
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1361:{\displaystyle T\setminus \{v_{0}\}}
261:This article is within the scope of
1640:Diagrams would be nice, of course.
1613:The proof would go something like:
536:vertices, and tournament matrix. --
207:It is of interest to the following
23:for discussing improvements to the
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281:Knowledge:WikiProject Mathematics
849:This has since been clarified. —
359:largest transitive subtournament
284:Template:WikiProject Mathematics
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1599:is a directed path as desired.
1412:be maximal such that for every
645:Theorem about Hamiltonian paths
1438:there is a directed edge from
1177:, and consider any tournament
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388:Last Sentence Paths and Cycles
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1270:and consider a directed path
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565:21:57, 14 February 2013 (UTC)
434:19:49, 25 November 2010 (UTC)
417:19:28, 25 November 2010 (UTC)
382:11:46, 24 November 2010 (UTC)
334:18:36, 22 February 2008 (UTC)
275:and see a list of open tasks.
42:Put new text under old text.
1711:C-Class mathematics articles
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515:12:28, 16 August 2012 (UTC)
485:10:51, 16 August 2012 (UTC)
50:New to Knowledge? Welcome!
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1223:vertices. Choose a vertex
881:Paradoxical vs. Transitive
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1670:16:53, 24 June 2017 (UTC)
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80:Be welcoming to newcomers
25:Tournament (graph theory)
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776:for clarity purposes. --
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303:project's priority scale
1431:{\displaystyle j\leq i}
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